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Force is applied on an object of mass 2 kg at reston a frictionless horizontal surface as shown in thegraph. The speed of object at t 1 s will beF(N)20t(s)(2) 12.5 m/s(4) 25 m/s5 10(1) 7.5 m/s(3) 10 m/s |
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Answer» on dividing the force co-ordinate , we get acceleration time graph as peak acceleration at t=0. that is 10m/s² . so acceleration is constant till t=5 sec , so , for 1 sec the velocity = at = 10m/s |
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