Force resisting the upward motion of a body on an inclined plane is given by (alpha – the angle of inclination, W- the weight of the body).(a) F = W×sin(alpha)(b) F = W×cosec(alpha)(c) F = W×sec(alpha)(d) F = W×cos(alpha)The question was posed to me during an interview.I would like to ask this question from Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives

Force resisting the upward motion of a body on an inclined plane is gi

1.	Force resisting the upward motion of a body on an inclined plane is given by (alpha – the angle of inclination, W- the weight of the body).(a) F = W×sin(alpha)(b) F = W×cosec(alpha)(c) F = W×sec(alpha)(d) F = W×cos(alpha)The question was posed to me during an interview.I would like to ask this question from Dynamics topic in portion Dynamics of Electrical Drives of Electric Drives
Answer» Right option is (a) F = W×sin(ALPHA) The explanation: When a body is MOVING upward on an inclined PLANE its weight can be resolved in two perpendicular components that are W×sin(alpha) and W×cos(alpha). W×cos(alpha) is the COMPONENT that is opposite to normal of the inclined plane and W×sin(alpha) is the component that opposes the upward MOTION of the body.

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