Saved Bookmarks
| 1. |
force year ago a father was 6 times as old as his son 10 years later the father will Bitto and half times at old as his son will be determined their percent age |
|
Answer» The son's AGE is 4% of his father's age. Son is 10 years old and father is 40 years old. Explanation: Let age of father be x and that of son be y. According to the question, x-4=6(y-4) x-4=6y-24 x=6y-20 - - - eqn.1 Also x+10=5/2(y+10) x+10=5y+50/2 2x+20=5y+50 - - eqn.2 SUBSTITUTING value of eqn.1 in eqn.2 2(6y-20)+20=5y+50 12y-40+20=5y+50 12y-5y=50+40-20 7y=70 y=10 Therefore x is equal to 40. We can GET this by Substituting value of y in eqn. 1 Thus, 10 ×40 /100=4% |
|