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Four identical solid spheres each of mass `M` and radius `R` are fixed at four corners of a light square frame of side length `4R` such that centres of spheres coincides with corners of square. The moment of inertia of `4` spheres about an axis perpendicular to the plane to frame and passing through its centre isA. `(21MR^(2))/5`B. `(42MR^(2))/5`C. `(84 MR^(2))/5`D. `(168 MR^(2))/5` |
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Answer» Correct Answer - D `I=4I_(1)` where `I_(1)` is `M.I.` of each sphere `I_(1)=I_(c)+Md^(2)` and `I_(c)=2/5 MR^(2), d=L/(sqrt(2)), L=4R` |
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