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Four particles each of mass `m` are placed at the corners of a square of side length `l`. The radius of gyration of the system about an axis perpendicular to the plane of square and passing through its centre isA. `l/(sqrt(2))`B. `l/2`C. `l`D. `sqrt(2)l` |
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Answer» Correct Answer - A `I=Sigmamr^(2)=4m[l/(sqrt(2))]^(2)=(4ml^(2))/2=2ml^(2)` Radius of gyration `k=sqrt(l/M)=sqrt((2ml^(2))/(4m))=l/(sqrt(2))` |
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