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Four particles of masses m, 2m, 3m and 4m arekept in sequence at the corners of a square of sidea. The magnitude of gravitational force acting ona particle of mass m placed at the centre of thesquare will be:24m2 G(1)6mFG(2)4-12G㎡(3)(4) Zero |
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Answer» Lets say, the force between the mass placed at the centre and the mass "m" at the corner A (say topleft) is F = Gm^2/(a/root[2])^2 So the other forces will be 2F, 3F and 4F towards B,C,D respectively (say B is top right) and so on. So the resultant Force will be 2root(2)F in the downward direction (vertical) which is 4root(2)Gm^2/a^2 (vertically downwards. {for this configuratoin of masses). |
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