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Four plates of the same area of cross-section are joined as shown in the figure. The distance each plate is `d`. The equivalent capacity across `A` and `B` will be A. `(2epsilon_(0)A)/(d)`B. `(3epsilon_(0)A)/(d)`C. `(3epsilon_(0)A)/(2d)`D. `(epsilon_(0)A)/(d)` |
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Answer» Correct Answer - B The given arrangement is equivalent to the parallel combination of three identical capacitors. Hence equivalent capacitance `= 3C = 3 (epsilon_(0)A)/(d)` |
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