1.

Four sources of sound each of sound level `10 dB` are sounded together in phase , the resultant intensity level will be `(log _(10) 2 = 0.3)`A. `40 dB`B. `26 dB`C. `22 dB`D. `13 dB`

Answer» Correct Answer - C
Resulant ampulitude will become `4` times.
Therefore , resultant intensity is `16` times
`L_(2) - L_(1) = log_(10) (I_(2))/(I_(1))`
or `I_(2) - 10 = 10 log _(10) (16)`
or `L_(2) = 22 dB`


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