1.

Four years ago, the father's age was three time the age of his son. The total of the ages of the father and the son after four years, will be 64 years. What is the father's age at present?1. 35 years2. 36 years3. 46 years4. None of these

Answer» Correct Answer - Option 4 : None of these

Given:

4 years ago, Father's age =3× Son's age

Sum of Father's age and Son's age = 64 years

Calculation:

Let the Father's present age and Son's present age be x years and y years respectively

According to the question

Four years ago, father's age = 3× Son's age

⇒ (x − 4) = (y − 4) × 3

⇒ x = 3y − 8 ----(1)

After 4 years, Sum of Father's age and Son's age= 64

⇒ (x + 4) + (y + 4) = 64

⇒ x + y = 56

⇒ y = 56 - x ----(2)

Putting the value of y inequation (1), we get

x = 3y − 8

⇒ x = 3(56 - x) - 8

⇒ x =3 × 56 − 3x − 8

⇒ 4x = 160

⇒ x = 160/4 = 40

∴ The Father's present age is 40 years.


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