InterviewSolution
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InterviewSolution
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\(\frac{cos\,\theta}{1-sin\,\theta}+\frac{cos\,\theta}{1+sin\,\theta}\) equals(a) 2 tan θ (b) 2 cosec θ (c) 2 cot θ (d) 2 sec θ |
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Answer» (d) 2 sec θ \(\frac{cos\,\theta}{1-sin\,\theta}+\frac{cos\,\theta}{1+sin\,\theta}\) = \(\frac{cos\,\theta(1+sin\,\theta)+cos\,\theta(1-sin\,\theta)}{(1-sin\,\theta)(1+sin\,\theta)}\) = \(\frac{cos\,\theta+cos\,\theta\,sin\,\theta+cos\,\theta-cos\,\theta\,sin\,\theta}{1-sin^2\,\theta}\) = \(\frac{2cos\,\theta}{cos^2\,\theta}= \frac{2}{cos\,\theta}\) = 2 sec θ |
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