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\frac{x+y-8}{2}=\frac{x+2y-14}{3}=\frac{3x-y}{4} 2 x+y−8 ​ = 3 x+2y−14 ​ = 4 3x−y ​

Answer» TION:Given, 2x+y−8= 3x+2y−14 = 43x−y By TAKING first two. we get,2x+y−8= 3x+2y−14 ⇒3x+3y−24=2x+4y−28⇒x−y=−4 By taking LAST two. we get,3x+2y−14 = 43x−y ⇒4x+8y−56=9x−3y⇒5x−11y=−56


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