InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
From the following bond energies: `H--H` bond energy: `431.37KJmol^(-1)` `C=C` bond energy: `606.10KJmol^(-1)` `C--C` bond energy: `336.49KJmol^(-1)` `C--H` bond energy: `410.50KJmol^(-1)` Enthalpy for the reaction will be: `overset(H)overset(|)underset(H)underset(|)(C)=overset(H)overset(|)underset(H)underset(|)(C)+H-H to Hoverset(H)overset(|)underset(H)underset(|)(C)-overset(H)overset(|)underset(H)underset(|)(C)-H`A. `553.0 kJ mol^(-1)`B. `1523.6 kJ mol^(-1)`C. `-243. kJ mol^(-1)`D. `-120.0 kJ mol^(-1)` |
|
Answer» Correct Answer - D `Delta H= Sigma (B.E.)_(R )- Sigma (B.E.)_(P)` `Delta H=[4xx(B.E.)_(H-H)+1xx(B.E.)_(C=C)+1xx(B.E.)_(H-H)]-[6xx(B.E.)_(H-H)+1xx(B.E.)_(C-C)]` |
|