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From the following thermochemical equations, calculate the standard enthalpy of formation of HCl(g) . (A) `H_(2)(g) rarr 2H(g) , DeltaH^(0)= + 436.0 kJ mol^(-1) ` (B) ` Cl_(2)(g) rarr 2Cl(g), DeltaH^(0)= + 242.7 kJ mol^(-1)` (C ) `HCl(g) rarr H(g) + Cl(g) , DeltaH^(0) = + 431.8 kJ mol^(-1)` |
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Answer» Correct Answer - `-92.45kJ mol^(-1)` Aim `: (1)/(2) H_(2)(g) + (1)/(2) Cl_(2)(g) rarrHCl(g)` |
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