1.

Gaseous `N_(2)O_(5)` decomposes according to the following equation: `N_(2)O_(5)(g) rarr 2NO_(2)(g) + (1)/(2)O_(2)(g)` The experimental rate law is `-Delta [N_(2)O_(5)]//Delta t = k[N_(2)O_(5)]`. At a certain temerature the rate constant is `k = 5.0 xx 10^(-4) sec^(-1)`. In how seconds will the concentration of `N_(2)O_(5)` decrease to one-tenth of its initial value ?A. `2.0 xx 10^(3)s`B. `4.6 xx 10^(3)s`C. `2.1 xx 10^(2)s`D. `1.4 xx 10^(3) s`

Answer» Correct Answer - B
`t = (2.303)/(5 xx 10^(-4)) "log"(A_(0))/(A_(0)//10)`
`= 4.6 xx 10^(3) sec`.


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