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Given a > 0, b > 0, a > b and c ≠ 0, the inequality which is not always correct is(a) a – c > b – c (b) \(\frac{a}{c^2}>\frac{b}{c^2}\)(c) a + c > b + c (d) ac > bc |
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Answer» (d) ac > bc a > b ⇒ ac > bc when c > 0, but a > b ⇒ ac < bc when c < 0. ∴ ac > bc is not always correct. |
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