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Given a = 7, a13 = 35, find d and S13. |
Answer» Given: a = 7; a13 = a + 12d = 35 ⇒ 7 + 12d = 35 ⇒ 12d = 35 – 7 ⇒ n = \(\frac{28}{12}\) = \(\frac{7}{3}\) Now, Sn = \(\frac{n}{2}\)(a + l) S13 = \(\frac{13}{2}\)(7 + 35) = \(\frac{13}{2}\) × 42 = 13 × 21 = 273 |
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