Given ∠A = 75°, ∠B = 30°, then tan (A-B) = ………A) √3B) 1/

1.	Given ∠A = 75°, ∠B = 30°, then tan (A-B) = ………A) √3B) 1/√3C) 1D) 1/√2
Answer» Correct option is: C) 1 <A = \(75^\circ\) & B = \(30^\circ\) \(\therefore\) A -B = \(75^\circ\) - \(30^\circ\) = \(45^\circ\) \(\therefore\) tan (A-B) = tan (\(45^\circ\)) = 1 Correct option is: C) 1

Given ∠A = 75°, ∠B = 30°, then tan (A-B) = ………A) √3B) 1/√3C) 1D) 1/√2

Answer»

Correct option is: C) 1

<A = \(75^\circ\) & B = \(30^\circ\)

\(\therefore\) A -B = \(75^\circ\) - \(30^\circ\) = \(45^\circ\)

\(\therefore\) tan (A-B) = tan (\(45^\circ\)) = 1

Correct option is: C) 1