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Given an idealgas is expanded adiabatically and irreversibley form volume `V_(1)` to `V_(2))` , then which one of the following is correct ?A. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= + ve`B. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= 0`C. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= 0`D. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= -ve` |
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Answer» Correct Answer - a For adiabatic process,`q=0` and hence `DeltaS` ( system ) `= 0` . Irrevrsible process is accompaniedby increase of entropy, therefore,`DeltaS` ( surrounding) `= + ve`. |
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