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Given: `E_(Zn^(+2)//Zn)^(@) =- 0.76V` `E_(Cu^(+2)//Cu)^(@) = +0.34V` `K_(f)[Cu(NH_(3))_(4)]^(2+) = 4 xx 10^(11)` `(2.303R)/(F) = 2 xx 10^(-4)` At what concentration of `Cu^(+2)` emf of the cell will be zero (at 298K) and concentration of `Zn^(+2)` is remains same:A. `1.19xx10^(-37)`B. `1.19xx10^(-20)`C. `3.78xx10^(-4)`D. `0.0068`

Answer» Correct Answer - A


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