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    				| 1. | Given f”(x) = 6x + 6, f'(0) = -5 and f(1) = 6 find f(x) | 
| Answer» f” (x) = 6x + 6 ⇒ f ‘ (x) = (6x + 6) dx = 6x2/2 + 6x + c = 3x2 + 6x + c Given f ‘(0) = -5 ⇒ 0 + c = -5 ⇒ c = -5 ∴ f ‘(x) = 3x2 + 6x – 5 So f(x) = ∫(3x2 + 6x - 5) dx = 3x3/3 + 6x2/2 – 5x + c (i.e.,) f(x) = x3 + 3x2 – 5x + c Given f(1) = 6 ⇒ 1 + 3 + 5 + c = 6 ⇒ c – 1 = 6 ⇒ c = 7 So f(x) = x3 + 3x2 – 5x + 7 | |