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Given `: N_(2)(g) + 3H_(2)(g)rarr2NH_(3)(g), Delta_(r)H^(@) +- 92.4 kJ mol^(-1)`. What is the standard enthalpy of formation of `NH_(3)` gas ? |
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Answer» Reaction for the enthalpy of `NH_(3)(g) ` is `: (1)/(2) N_(2)(g) +(3)/(2) H_(2)(g) rarr NH_(3)(g)` `:. Delta_(f)H^(@) = - 92.4//2 = - 46.2 kJ mol^(-1)` |
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