InterviewSolution
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InterviewSolution
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Given: `NaCI(s) +aq rarr Na^(o+) (aq) +CI^(Theta) DeltaH = 3.9 kJ` `Na^(o+)(g) +CI^(Theta)(g) rarr NaCI(s) DeltaH =- 788 kJ` `CI^(Theta)(g)+aq rarr CI^(Theta)(aq) DeltaH =- 394.1 kJ` Calculate the enthalpy of hydration of `Na^(o+)` ions. |
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Answer» `Na^(o+) (g) +aq rarr Na^(o+) (aq) DeltaH = ?` `DeltaH = DeltaH_(1) +DeltaH_(2) - DeltaH_(3)` `= 3.9 - 788 -(-394.1)` `= 3.9 - 788 +394.1 =- 390.0 kJ` |
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