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Given that sinθ = a/b , then cosθ is equal to(A) b/√(b2– a2) (B) b/a (C) √(b2-a2)/b (D) a/√(b2-a2) |
Answer» (C) √(b2-a2)/b According to the question, sin θ =a/b We know, sin2 θ +cos2 θ =1 sin2 A = 1-cos2 A sin A = √(1-cos2 A So, cos θ = √(1-a2/b2 ) = √((b2-a2)/b2 ) = √(b2-a2 )/b Hence, cos θ = √(b2 – a2 )/b |
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