InterviewSolution
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InterviewSolution
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Given the following thermochemical equations `:` (i) S( rhombic ) `+ O_(2)(g) rarr SO_(2)(g) , Delta H = - 297.5 kJ mol^(-1)` (ii) S ( monoclinic) `+ O_(2) rarr SO_(2)(g) , Delta H = - 300.0 kJ mol^(-1)` Calculate `Delta H ` for the transformation of one gram atomof rhombic sulphur into monochlinic sulphur. |
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Answer» We aim at `:` S ( rhombic ) `rarr ` S ( monoclinic) , `Delta H = ?` Equation (i) - Equation (ii) gives S ( rhombic ) - S ( monoclinic ) ` rarr 0 , Delta = 297.5 - ( - 300.0) = 2.5 kJ mol^(-1)` or S( rhombic ) `rarr ` S ( monoclinic ) , `Delta H = + 2.5 kJ mol^(-1)` Thus, for the transformation of one gram atom of rhombic sulphur into monoclinic sulphur, `2.5 kJ mol^(-1)` of heat is absorbed. |
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