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Given the minimum force applied in parallel to the liquid to move an object of mass 100 g in the microscopic area, the material coefficient of friction is 0.4 |
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Answer» Given: Given the MINIMUM force applied in parallel to the liquid to move an object of mass 100 g in the MICROSCOPIC AREA, the material COEFFICIENT of friction is 0.4 To find: The minimum force applied. Solution: From given, we have, The mass of object = m = 100 g The coefficient of friction = μ = 0.4 As the minimum force applied in parallel to the liquid, so we have, θ = 0° we use the formula, f = μmg cos θ f = 0.4 × 100 × 9.8 × cos 0° f = 392 N Therefore, the minimum force applied is 392 N |
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