1.

Given the minimum force applied in parallel to the liquid to move an object of mass 100 g in the microscopic area, the material coefficient of friction is 0.4​

Answer»

Given:

Given the MINIMUM force applied in parallel to the liquid to move an object of mass 100 g in the MICROSCOPIC AREA, the material COEFFICIENT of friction is 0.4

To find:

The minimum force applied.

Solution:

From given, we have,

The mass of object = m = 100 g

The coefficient of friction = μ = 0.4

As the minimum force applied in parallel to the liquid, so we have, θ = 0°

we use the formula,

f = μmg cos θ

f = 0.4 × 100 × 9.8 × cos 0°

f = 392 N

Therefore, the minimum force applied is 392 N



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