1.

h : A → B, A = {1, 2, 3},B = {3, 4, 5, 6, 7, 8}, h (x) = x + 5.State the type of function h.

Answer»

h : A → B

A = {1, 2, 3} and h (x) = x + 5

∴ h (1) = 1 + 5 = 6, h (2) = 2 + 5 = 7, h (3) = 3 + 5 = 8

B = {3, 4, 5, 6, 7, 8}

For the elements 1, 2, 3 of domain

h (1) ≠ h (2) ≠ h (3).

Therefore, function ft is one-one function.



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