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h : A → B, A = {1, 2, 3},B = {3, 4, 5, 6, 7, 8}, h (x) = x + 5.State the type of function h. |
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Answer» h : A → B A = {1, 2, 3} and h (x) = x + 5 ∴ h (1) = 1 + 5 = 6, h (2) = 2 + 5 = 7, h (3) = 3 + 5 = 8 B = {3, 4, 5, 6, 7, 8} For the elements 1, 2, 3 of domain h (1) ≠ h (2) ≠ h (3). Therefore, function ft is one-one function. |
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