Half life period for a reaction `A to` Products at 298 K is 3.33 hours. Calcualte the rate constant for the reaction. If the reaction is started from one mole of A, what amount of A would remain unreacted at the end of 9 hours?

Half life period for a reaction `A to` Products at 298 K is 3.33 hours

1.	Half life period for a reaction `A to` Products at 298 K is 3.33 hours. Calcualte the rate constant for the reaction. If the reaction is started from one mole of A, what amount of A would remain unreacted at the end of 9 hours?
Answer» Step i. Calculation of the rate constant. Rate constant(k)`=(0.693)/(t_(1//20))= (0.693)/(3.33 "hours")=0.2081 hr^(-1)` Step II. Calculation of amount of A left unreacted `k=0.2081 hr^(-1)`, a=1mol, t=9 hours. `k=2.303/t log a/(a-x)` `log a/(a-x) = (kxxt)/(2.303) = (0.2081 hr^(-1) xx 9hr)/(2.303) = 0.8133` `a/(a-x) = "Antilog" 0.8133=6.506` `(a-x) = a/6.506 = 1/(6.506)=0.1538` mol

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Half life period for a reaction `A to` Products at 298 K is 3.33 hours. Calcualte the rate constant for the reaction. If the reaction is started from one mole of A, what amount of A would remain unreacted at the end of 9 hours?

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