1.

Half-life period of a first-order reaction is `1386` seconds. The specific rate constant of the reaction isA. `0.5xx10^(-2)s^(-1)`B. `0.5x10^(-3)s^(-1)`C. `5.0xx10^(-2)s^(-1)`D. `5.0xx10^(-3)s^(-1)`

Answer» Correct Answer - B
For the first order reaction
`t_(1//2)=(0.693)/(k)`
Thus,
`k=(0.693)/(t_(1//2))`
`=(0.693)/(1386s)=0.0005s^(-1)`
`0.5xx10^(-3)s^(-1)`


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