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Half-life period of a first-order reaction is `1386` seconds. The specific rate constant of the reaction isA. `0.5xx10^(-2)s^(-1)`B. `0.5x10^(-3)s^(-1)`C. `5.0xx10^(-2)s^(-1)`D. `5.0xx10^(-3)s^(-1)` |
Answer» Correct Answer - B For the first order reaction `t_(1//2)=(0.693)/(k)` Thus, `k=(0.693)/(t_(1//2))` `=(0.693)/(1386s)=0.0005s^(-1)` `0.5xx10^(-3)s^(-1)` |
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