Half-power Beam width in E-plane for a rectangular aperture antenna of a×bis given by ____(a) 0.886λ/b(b) 0.443λ/b(c) 0.5λ/b(d) λ/bThis question was addressed to me at a job interview.The doubt is from Aperture Antenna in chapter Aperture Antenna of Antennas

Half-power Beam width in E-plane for a rectangular aperture antenna of

1.	Half-power Beam width in E-plane for a rectangular aperture antenna of a×bis given by ____(a) 0.886λ/b(b) 0.443λ/b(c) 0.5λ/b(d) λ/bThis question was addressed to me at a job interview.The doubt is from Aperture Antenna in chapter Aperture Antenna of Antennas
Answer» RIGHT option is (a) 0.886λ/b The explanation: By equating the field in E-plane to HALF power point \(\frac{sin⁡(0.5kbsin\theta)}{0.5kbsin\theta} = \frac{1}{\sqrt 2}=> \theta = arcsin⁡(\frac{0.443 \lambda}{b})\) Now HPBW = 2 arcsin⁡\((\frac{0.443\lambda}{b})\)≈0.886λ/b.

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Half-power Beam width in E-plane for a rectangular aperture antenna of a×bis given by ____(a) 0.886λ/b(b) 0.443λ/b(c) 0.5λ/b(d) λ/bThis question was addressed to me at a job interview.The doubt is from Aperture Antenna in chapter Aperture Antenna of Antennas

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