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he angular displacement of a particle is givenbyD. Tθ = t3 + t2 + t + 1 then, its angular velocityat t 2 sec is. rads1) 27In the above problem, the angular accelerationof the particle at t 2 sec is.. rads2) 173) 154) 16.2 |
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Answer» angular velocity is d∅/dt = 3t²+2t+1 at t = 2sec , d∅/dt = 3*(2)²+2*(2)+1 = 12+4+1 = 17 rad-¹ angular acceleration = d²∅/dt² = 6t+2 at t = 2 => d²∅/dt² = 6(2)+2 = 14 rad-² |
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