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Heat of combustion of ethanol at constant pressure and at temperature T K(=298 K) is found to be -qJ `"mol"^(-1)`. Hence , heat of combustion (in J `"mol"^(-1)`) of ehtanol at the same temperature at constant volume will be:A. RT-qB. `-(q+RT)`C. q-RTD. q+RT |
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Answer» Correct Answer - A `C_(2)H_(5)OH(l) + 3O_(2)(g) rarr 3H_(2)O(r)` `Deltan_(3)=2-3=-1` so `DeltaU=DeltaH-Deltan_(g)RT` `=-q+RT` |
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