InterviewSolution
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InterviewSolution
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Height of a cylindrical iron rod is four times to its radius of the base. If it is melted and recast into spherical balls, number of balls thus formed A) 4 B) 3 C) 2 D) 1 |
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Answer» Correct option is: B) 3 Given that h = 4 r \(\therefore\) Volume of cylindrical iron rod = \(\pi r^2h\) = \(4 \pi r^3\) (\(\because\) h = 4r) \(\because\) Cylindrical iron rod is melted and recast into n spherical balls. Then n \(\times\) volume of one spherical ball = Volume of cylindrical iron rod \(\Rightarrow\) n = \(\frac {Volume \, of \, cylindrical \, iron \, rod}{Volume \, of \, one \, spherical\, ball}\) = \(\frac {4 \pi r^3}{\frac 43 \pi r^3 }\) (\(\because\) r is also radius of formed spherical ball) = 3 Hence, number of balls thus formed is 3. Correct option is: B) 3 |
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