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Answer» m = MO / √ 1-(x^2 /c^2 ),[LHS ]=[M]=[RHS] so 1-(x^2/c^2) is dimensionless .HENCE (x^2/c^2) is dimensionless .this MEANS that x and c have the same dimensions ,i.e, [x]= [c] = [ LT^ -1]

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m = MO / √ 1-(x^2 /c^2 ),[LHS ]=[M]=[RHS] so 1-(x^2/c^2) is dimensionless .HENCE (x^2/c^2) is dimensionless .this MEANS that x and c have the same dimensions ,i.e, [x]= [c] = [ LT^ -1]

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