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Here is intresting ques.for u ..six years before age of motherwas equal to square of her sons age. three years hence,her age will be thrice the age of sonthen.FIND PRESENT AGES OF MOTHER AND SON............ |
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Answer» Persent age of mother = x2+6⇒36+6=42 SON = x+6=6+6=12 Explanation: Let age of son 6 years before be x then mother's age = x2 then, persent age son =x+6 mothers age =x2+6 After 3 YEAR, son =x+6+3=x+9 mother =x2+6+3=x2+9 A.T.Q x2+9=3(x+9) x2+9=3x+27 x2−3x−18=0 x2−6x+3x−18=0 x(x−6)+3(x−6)=0 (x+3)(x−6)=0 x=6 (-3 will NEGLECT) Persent age of mother = x2+6⇒36+6=42 Son = x+6=6+6=12 |
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