1.

Hey guys...solve this if anyone can...find the derivative of x-1/√(x+1)​

Answer»

Explanation

y

=

√

x

−

1

x

+

1

taking natural log of both sides,

ln

y

=

1

2

ln

(

x

−

1

x

+

1

)

,

ln

y

=

1

2

(

ln

(

x

−

1

)

−

ln

(

x

+

1

)

)

differentiating both sides with RESPECT to

x

,

1

y

⋅

y

'

=

1

2

(

1

x

−

1

−

1

x

+

1

)

y

'

=

y

2

(

x

+

1

−

x

+

1

x

2

−

1

)

y

'

=

y

(

1

x

2

−

1

)

PLUGGING

y

y

'

=

(

√

x

−

1

x

+

1

)

(

1

x

2

−

1

)

y

'

=

(

√

x

−

1

x

+

1

)

(

1

(

x

−

1

)

(

x

+

1

)

)

y

'

=

1

√

x

−

1

(

x

+

1

)

3

2


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