InterviewSolution
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InterviewSolution
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हल कीजिए `(dy)/(dx) =(4x + y+1)^(2).` |
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Answer» यहाँ `(dy)/(dx)=(4x+y+1) ^(2)" "...(1)` माना ` 4x+y+1 =v" "...(2)` x के सापेक्ष अवकलन करने पर, `4+(dy)/(dx)=(dv)/(dx)` `implies(dy)/(dx) =(dv)/(dx) -4" "...(3)` समी (1),(2) और (3)से, `(dv)/(dx)=v^(2) ` `implies (dv)/(dx) =v^(2) +4` `implies (1)/(v^(2) +4)dv= dx` समाकलन करने पर, `int (1)/(v^(2)+2^(2))dv=int dx` `int (1)/(v^(2) +2^(2))dc =int dx` `implies 1/2 tna ^(-1) ((v)/(2)) =x+C` `implies1/2 tan^(-1)((4x+y+1)/(2))=x+C.` |
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