1.

हल कीजिए `(dy)/(dx) =cos (x+y)`

Answer» दिया गया अवकल समीकरण है-
`(dy)/(dx)=cos (x+y)" "...(1)`
माना `x+y=v" "...(2)`
x के सापेक्ष अवकलन करने पर,
`1+(dy)/(dx)=(dc)/(dx)`
`implies (dy)/(dx) =(dv)/(dx)-1" "...(3)`
समी (1),(2) और (3) से,
`implies (dv)/(dx)-1 =cos v`
`implies (dv)/(dx) =1+cos v`
`implies (dv)/(dx) =2 cos ^(2) v/2,`
`[because cos 2 theta =2 cos ^(2) theta -1]`
`1/2 (1)/(cos ^(2)""v/2)dv =intdx`
`implies1/2 int sec ^(2)"" v/2 dv= x+C`
`implies tan ""(v)/(2) =x+C`
`implies tan ((x+y))/(2) =x+C.`


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