InterviewSolution
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हल करें (i) `cos6x+cos4x= sin 3x+sinx` (ii) `cos5x+cos3x+cosx=0` `(iii) cos theta-sin3 theta=cos2 theta` `(iv) cos x+cos3x+cos5x+cos7x+0` (v) `sin 3 theta+sin2 theta+ sin theta =0` (vi) `sin 2x-sin4x+sin6x=0` |
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Answer» Correct Answer - `(i) (2n+1)(pi)/(2),(4n+1)(pi)/(14)(4n-1)(pi)/(6)n in I` (ii) `(2n+1)(pi)/(6), n pi +-(pi)/(3), n in I " " (iii) (2npi)/(3),(4n+1)(pi)/(4),(4n-1)(pi)/(2)n in I` (iv) ` (2n+1)(pi)/(6),(2n+1)(pi)/(4),(2n+1) pi` (v) `(npi)/(2), 2n pi+-(2pi)/(3), n in I " " (vi) n=(n pi)/(4)` या `x=npi+-(pi)/(6), n in Z` |
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