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हल करें `sin theta =-(sqrt(3))/(2)` |
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Answer» प्रश्न से `sin theta=-(sqrt(3))/(2)=sin (-(pi)/(3))` `:. theta =n pi +(-1)^(n)(-(pi)/(3))` अतः `theta=npi-(-1)^(n)(pi)/(3), n=0pm1pm2` |
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