1.

हल करें `sin theta =-(sqrt(3))/(2)`

Answer» प्रश्न से `sin theta=-(sqrt(3))/(2)=sin (-(pi)/(3))`
`:. theta =n pi +(-1)^(n)(-(pi)/(3))`
अतः `theta=npi-(-1)^(n)(pi)/(3), n=0pm1pm2`


Discussion

No Comment Found

Related InterviewSolutions