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How does the capacitance change with the effect of the dielectric when the battery is kept disconnected from the capacitor?(a) Increases(b) Decreases(c) Remains constant(d) ZeroI got this question in homework.Query is from Effect of Dielectric on Capacitance topic in chapter Electrostatic Potential and Capacitance of Physics – Class 12

Answer»

Right answer is (a) Increases

For explanation: When the battery is disconnected, and a DIELECTRIC is INTRODUCED, there will be a decrease in potential difference and as a result, the CAPACITANCE increases k times.

C = \(\FRAC {Q_0}{V}\)

C = \( [ \frac {Q_0}{(\frac {V_0}{k})} ] \)

C = \(\frac {kQ_0}{V_0}\)

C = kC0.



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