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How is negative of an image obtained with intensity levels [0,L-1] with “r” and “s” being pixel values?(a) s = L – 1 + r(b) s = L – 1 – r(c) s = L + 1 + r(d) s = L + 1 + rI had been asked this question by my school teacher while I was bunking the class.This is a very interesting question from Intensity Transformation Functions topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing |
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Answer» RIGHT OPTION is (b) s = L – 1 – r Easiest explanation: The negative is obtained using s = L – 1 + r. |
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