How many 176 Ω resistors (in series) are required to carry 5 A on a

1.	How many 176 Ω resistors (in series) are required to carry 5 A on a 220 V line?
Answer» Answer: , For x NUMBER of resistors of resistance 176 Ω, Here ,Supply voltage, V = 220 V Current, I = 5 A Equivalent resistance of the combination = R, given as $\frac{1}{r} = x \times ( \frac{1}{176} )$ $r = \frac{176}{x}$ From Ohm’s law, $\frac{v}{i} = \frac{176}{x}$ $x = \frac{176 \times i}{v}$ $x = \frac{176 \times 5}{220}$ $x = 4$ ∴four resistors of 176 Ω are REQUIRED to draw the given AMOUNT of current. HOPE IT HELPS YOU PLEASE MARK ME AS BRAINLIST..