How many 7060 ohm resistor in parallel are required to 5 ampere on a 1

1.	How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt
Answer» Answer: QUESTION: How many 7060 ohm resistor in PARALLEL are required to 5 ampere on a 16 volt. GIVEN: resistance of one resistor , r=7060 ohm current, I = 5 ampere potential difference , V = 16 volt TO FIND: number of resistors connected in parallel, n FORMULA: if n resistors of equal resistance are connected in parallel, then the resultant resistance will be, R=r/n where, R is the net resistance r is the INDIVIDUAL resistance n is the number of resistors. according to OHM'S LAW, V=IR SOLUTION: STEP 1: TO FIND THE NET RESISTANCE: R=r/n R=7060/n STEP 2: APPLY OHM'S LAW: V=IR $16 = 5 \times \frac{7060}{n} \\ \\ \frac{16}{5} = \frac{7060}{n } \\ \\ \frac{5}{16} = \frac{n}{7060} \\ \\ n = 7060 \times \frac{5}{16} \\ \\ n = 441.25 \times5 \\ \\ n =2206.25$ ANSWER: therefore 2206.25 resistors are connected in parallel. since the number of resistors can not be in DECIMAL, the above combination is not possible practically

How many 7060 ohm resistor in parallel are required to 5 ampere on a 16 volt

Answer»

Answer:

QUESTION:

How many 7060 ohm resistor in PARALLEL are required to 5 ampere on a 16 volt.

GIVEN:

resistance of one resistor , r=7060 ohm

current, I = 5 ampere

potential difference , V = 16 volt

TO FIND:

number of resistors connected in parallel, n

FORMULA:

if n resistors of equal resistance are connected in parallel, then the resultant resistance will be,

R=r/n

where,

R is the net resistance
r is the INDIVIDUAL resistance
n is the number of resistors.

according to OHM'S LAW,

V=IR

SOLUTION:

STEP 1:

TO FIND THE NET RESISTANCE:

R=r/n

R=7060/n

STEP 2:

APPLY OHM'S LAW:

V=IR

$16 = 5 \times \frac{7060}{n} \\ \\ \frac{16}{5} = \frac{7060}{n } \\ \\ \frac{5}{16} = \frac{n}{7060} \\ \\ n = 7060 \times \frac{5}{16} \\ \\ n = 441.25 \times5 \\ \\ n =2206.25$

ANSWER:

therefore 2206.25 resistors are connected in parallel.

since the number of resistors can not be in DECIMAL, the above combination is not possible practically