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How many bulbs of resistance 6 9 should bejoined in parallel to draw a current of 2 A from abattery of 3 V?

Answer»

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▶️Suppose n resistances of 6 ohm are connected in parallel and the resultant resistance=R

▶️1/R=n/6=>R=6/n

▶️Now Current I=2 A,Voltage V=3 volts

▶️By ohm's law V=IR

▶️3=2x6/n

▶️n=4

▶️▶️Hence 4 bulbs are connected in parallel.

3 is the correct answer

3 is the correct answer of the given question

3 bulbs, that's the right answer of this question



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