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How many bulbs of resistance 6 9 should bejoined in parallel to draw a current of 2 A from abattery of 3 V? |
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Answer» ___________________________ ▶️Suppose n resistances of 6 ohm are connected in parallel and the resultant resistance=R ▶️1/R=n/6=>R=6/n ▶️Now Current I=2 A,Voltage V=3 volts ▶️By ohm's law V=IR ▶️3=2x6/n ▶️n=4 ▶️▶️Hence 4 bulbs are connected in parallel. 3 is the correct answer 3 is the correct answer of the given question 3 bulbs, that's the right answer of this question |
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