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How many grams of potassium chloride is present in 250 g of saturated solution ? The solubility of KCl is 35.8 at 25^(@)C ? |
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Answer» Solution :Solubility` = ("Mass of solute")/("Mass of solvent") XX 100` `35.8 = (X)/(250 -x) xx 100` `(250 - x)35.8 = 100 x rArr 8950 - 35.8 x = 100x rArr x = 65.9 G` |
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