1.

How many grams of potassium will have the same number of atoms as 6 grams of sodium ? (Atomic mass of Na = 23, K = 39)

Answer»

Solution :Number of SODIUM atoms
`= ("given mass")/("molar mass") xx "Avogadro number"`
`=(6)/(23) xx 6.022 xx 10^(23) ~~ 1.57 xx 10^(23)`
Number of potassium atoms present in 39 g = `6.022 xx 10^(23)`
`:.` 1 ATOM of K is present in`(39)/(6.023 xx 10^(23))`
`:. 1.57 xx 10^(23)` atoms of K are present in `(39 xx 1.57 xx 10^(23))/(6.022 xx 10^(23)) g ~~ 10.17 g`
10.17 g of potassium.


Discussion

No Comment Found