How many minimal forms are there in the function F(A, B, C) = ∑(1, 3, 2, 5, 6, 7) if it is having cyclic prime implicants k-map?(a) 216(b) 2(c) 14(d) 82I have been asked this question in a job interview.Enquiry is from Boolean Algebra topic in division Boolean Algebra and Modeling Computations of Discrete Mathematics

How many minimal forms are there in the function F(A, B, C) = ∑(1, 3

1.	How many minimal forms are there in the function F(A, B, C) = ∑(1, 3, 2, 5, 6, 7) if it is having cyclic prime implicants k-map?(a) 216(b) 2(c) 14(d) 82I have been asked this question in a job interview.Enquiry is from Boolean Algebra topic in division Boolean Algebra and Modeling Computations of Discrete Mathematics
Answer» Correct answer is (b) 2 To elaborate: In cyclic prime IMPLICANT, min terms will be (1, 3, 5, 7, 9, 11). Hence, either we can have [(1,3), (7,11), (5,9)] or [(1,5), (11,9), (3.7)]. So, there can be 2 minimal forms.

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