InterviewSolution
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InterviewSolution
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Simplify the expression XZ’ + (Y + Y’Z) + XY.(a) (1+XY’)(b) YZ + XY’ + Z’(c) (X + Y +Z)(d) XY’+ Z’I have been asked this question during an interview.This key question is from Minimization of Boolean Functions topic in portion Boolean Algebra and Modeling Computations of Discrete Mathematics |
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Answer» CORRECT CHOICE is (C) (X + Y +Z) To explain: GIVEN: X Z’ + (Y + Y’Z) + XY = XZ’ + (Y + Z) + XY = XZ’ + Y + Z + XY = (XZ’ + Z) + (Y + XY) = (X + Z) + Y (1 + X) = X + Y + Z. |
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