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How many moles are present in 11.5 g of sodium ?

Answer»

Solution :Gram atomic mass of SODIUM = 23 g
23 g of sodium represent = 1 mole
`THEREFORE 11*5` g of sodium represent `= ("(1 mol )" xx 11 * 5)/(23*0 g) = 0.5` mol
`6.022` atoms of element will have mass = `2xx 10^(-23) g xx 6*022 xx 10^(23)`
`= 12*044 g = 12 * 0` gram


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