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How many terms are there in the AP 41, 38, 35, …, 8? |
Answer» Given: AP is 41, 38, 35,…, 8 Here, first term = a = 41 Last term = 8 Common difference = d = 38 – 41 = -3 To find: the number of terms (n) Last term = a + (n – 1)d 8 = 41 + (n – 1)(-3) 8 – 41 = (n – 1)(-3) n – 1 = 11 n = 11 + 1 = 12 There are 12 terms. |
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